Daily JavaScript Challenge #JS-216: Count the Occurrences of Each Character in a String

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Daily JavaScript Challenge: Count the Occurrences of Each Character in a String

Hey fellow developers! 👋 Welcome to today's JavaScript coding challenge. Let's keep those programming skills sharp!

The Challenge

Difficulty: Medium

Topic: String Manipulation

Description

Given a string, write a JavaScript function that counts the occurrences of each character in the string (case-sensitive) and returns an object with characters as keys and their counts as values.

Ready to Begin?

https://www.dpcdev.com/

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Write your solution
Test it against the provided test cases
Share your approach in the comments below!

Want to Learn More?

Check out the documentation about this topic here: https://developer.mozilla.org/en-US/docs/Web/JavaScript/Reference/Global_Objects/Object

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This is part of our Daily JavaScript Challenge series. Follow me for daily programming challenges and let's grow together! 🚀

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Top comments (1)

Rusu Ionut • Jul 3

function count(s, c)
{
    let res = 0;

    for (let i = 0; i < s.length; i++)
    {
        // checking character in string
        if (s.charAt(i) == c)
        res++;
    } 
    return res;
}


    let str= "geeksforgeeks";
    const allCharacters = new Set(str.split(""));
    allCharacters.forEach(character=>{
       console.log(`carater: ${character} ${count(str, character)}`);
    });