Daily JavaScript Challenge #JS-216: Count the Occurrences of Each Character in a String

#javascript #devchallenge #programming #webdev

Daily JavaScript Challenge: Count the Occurrences of Each Character in a String

Hey fellow developers! 👋 Welcome to today's JavaScript coding challenge. Let's keep those programming skills sharp!

The Challenge

Difficulty: Medium

Topic: String Manipulation

Description

Given a string, write a JavaScript function that counts the occurrences of each character in the string (case-sensitive) and returns an object with characters as keys and their counts as values.

Ready to Begin?

https://www.dpcdev.com/

Fork this challenge
Write your solution
Test it against the provided test cases
Share your approach in the comments below!

Want to Learn More?

Check out the documentation about this topic here: https://developer.mozilla.org/en-US/docs/Web/JavaScript/Reference/Global_Objects/Object

Join the Discussion!

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This is part of our Daily JavaScript Challenge series. Follow me for daily programming challenges and let's grow together! 🚀

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Top comments (1)

Rusu Ionut • Jul 3

function count(s, c)
{
    let res = 0;

    for (let i = 0; i < s.length; i++)
    {
        // checking character in string
        if (s.charAt(i) == c)
        res++;
    } 
    return res;
}


    let str= "geeksforgeeks";
    const allCharacters = new Set(str.split(""));
    allCharacters.forEach(character=>{
       console.log(`carater: ${character} ${count(str, character)}`);
    });