Daily JavaScript Challenge #JS-124: Find Number of Vowels in a String

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Daily JavaScript Challenge: Find Number of Vowels in a String

Hey fellow developers! 👋 Welcome to today's JavaScript coding challenge. Let's keep those programming skills sharp!

The Challenge

Difficulty: Easy

Topic: String Manipulation

Description

Create a function that counts the number of vowels in a given string. Vowels include 'a', 'e', 'i', 'o', 'u', both uppercase and lowercase. The function should return the total count of vowels in the string.

Ready to Begin?

https://www.dpcdev.com/

Fork this challenge
Write your solution
Test it against the provided test cases
Share your approach in the comments below!

Want to Learn More?

Check out the documentation about this topic here: https://developer.mozilla.org/en-US/docs/Web/JavaScript/Reference/Global_Objects/String/toLowerCase

Join the Discussion!

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Did you find any interesting edge cases?
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This is part of our Daily JavaScript Challenge series. Follow me for daily programming challenges and let's grow together! 🚀

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Top comments (6)

Alex Lohr • Mar 13

const countVowels = word => [...word.toLowerCase()]
  .filter(c => "aeiou".includes(c))
  .length;

Massimo Artizzu • Mar 14

const vowelCount = word.split(/[aeiou]/i).length - 1;

A solution good for challenges, nothing more. Don't use it in your code.

na.perruchot • Mar 18 • Edited

const countVowels => (content) => 
   [...content.normalize("NFD").toLowerCase().match(/([aeiou])/igu)].length;

Misael Braga de Bitencourt • Mar 17 • Edited

const countVowels = word => {
    const vowels = [...'aeiouáéíóúâêîôûàèìòùãẽĩõũ'];
    return [...word.toLowerCase()].reduce((counter, current) => counter += vowels.indexOf(current) === -1 ? 0 : 1, 0);
}